81 is.
That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.
The largest remainder will be one less than the divisor. 7 - 1 = 6.
24
The GCF is 18.
If you divide by 8, the remainder can be any number from 0 to 7.
The largest number that will divide into 28 42 and 70 with no remainder is 14.
That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.
24. The largest remainder is always one less than the number by which you are dividing (the divisor).
The largest remainder will be one less than the divisor. 7 - 1 = 6.
24
The GCF is 18.
If you take the number 969 and subtract the 9 remainder you get 960. Because the number is even you can divide it by 2. 969/2 = 480R9. :)
The largest number that will divide evenly into 64 with no remainder is 64.
If you divide by 8, the remainder can be any number from 0 to 7.
Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).
You can't have a remainder of 6 when you divide by 2! JHC!
The largest remainder would be 8, because if it were 9 you could divide the number once more. The largest remainder you can have is always one less than what you're dividing by. So if you're dividing by 10, your largest remainder is 9. If you're dividing by 100, it's 99. And so on.