The largest whole number for x that satisfies this inequality is x = 0.
6x + 73 < 3x + 103x + 73 < 103x < -63x < -21The largest whole number that complies is -22.
81 is the largest square of a whole number...
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
25 is a perfect square25 is the largest whole number that is less than 26
An integer is a whole number, and the largest integer less than 9.5 would be 9.4
6x + 73 < 3x + 103x + 73 < 103x < -63x < -21The largest whole number that complies is -22.
81 is the largest square of a whole number...
97
The largest possible number for a remainder is 1 less than the number of the divisor, so it is 5.
25 is a perfect square25 is the largest whole number that is less than 26
An integer is a whole number, and the largest integer less than 9.5 would be 9.4
An integer is a whole number, and the largest integer less than 9.5 would be 9.4
599 if we're talking whole nos. only
Prime numbers can't have whole number square roots, of course, but the largest prime number under 400 is 397.
There is no whole number less than zero.
It depends: If the whole number is positive then the result is less than the whole number, eg ½ × 2 = 1 < 2 If the whole number is negative then the result is greater than the whole number, eg ½ × -2 = -1 > -2
There is no solution if the question asks for 'less than -1'. Suppose a is the largest number. Then we have -3+a<-1, so a<2. But then I can take the number x:=(a+2)/2. This number is still less than 2 (it is in the middle of 2 and a on the number line) and so -3+x<-1. But x>a, which contradicts a being the largest number satisfying the required property. If it's 'less than or equal to -1', you can take the number 2.