Lateral Area=Perimeter of the base * height
perimeter=20
height=6
so,
Lateral Area=20 * 6
Lateral Area=120cm
LA=1/2ps
LA=1/2ps
1/2 times the perimeter of the base times slant height
LA=1/2ps
it's the same as a rectangle. LA= Ph (Perimeter x's Height)
A = 2AB + AL AB = area of the base AL = lateral area = Perimeter X height
What makes this question tricky to answer is the understanding of the terms. Were the correct terms used in the question, and does the question poster and answer contributor have the same understanding of those terms? Having said that, here goes. A prism is a polyhedron with at least two congruent parallel faces. They are called the bases. The other faces (the "lateral faces") are parallelograms that are formed by lines that connect the corresponding vertices of the two bases. A quadrangular prism has a quadrangular base (such as a rectangle). If the base is some sort of regular polygon, it's called a regular prism. The lateral area of a prism is defined as the total area of the lateral faces. To calculate the lateral area, you multiply the length of an edge by the perimeter of the face that is perpendicular (at right angles to) to that edge. So, assuming the height, 4 cm in this case, is perpendicular to the perimeter, 16 cm, we calculate the lateral area to be 4 x 16 or 64 square centimeters or 64 cm2.
LA=1/2ps
LA=1/2ps
LA = 1/2psnewtest3
L=PH L=PH Lateral Area= (Perimeter of the base)(the height of the figure)
1/2 times the perimeter of the base times slant height
LA=1/2ps
The lateral area [L] of a right prism with base perimeter [P] and height [h] is L=Ph.
Probably you meant to ask what is the lateral area of a hexagonal prism. In that case, it would be the perimeter of one of the bases times the height.
1/2(p)(sh) ~which means~ 1/2 x perimeter x slant height slant height= pathagorean theory= c squared= a squared+b squared
it's the same as a rectangle. LA= Ph (Perimeter x's Height)