Using Pythagoras' theorem the height of the equilateral triangle works out as about 7 cm and so with the given dimensions it would appear to be quite difficult to work out the lateral area.
It is the perimeter of a triangle times the length of the prism (in square units).
47.88 cm2
Triangle
You can't.
isoscles triangle
It is the perimeter of a triangle times the length of the prism (in square units).
not necessarily... it can be any triangle.
Type your answer hereThe surface area of a prism is square root of 3* a 2 /4 + 3*a*h where a is edge of equilateral triangle and h is height of prism
47.88 cm2
Triangle
You can't.
The Formula is Base*Height, or 1/2 Height (altitude of the triangle) * Base (of the Triangle) * height (Height of the prism)
The height of the base is part of the triangle and the height of the prism is the height of the rectangle
The lateral area is the perimeter of the hexagon times the height (altitude length) of the prism. Same for any other prism.
isoscles triangle
Three congruent rectangles.
The lateral area L.A. of the right triangular prism is the sum of the areas of its lateral faces, which are rectangles with length the height (l = h = 15) and wide the sides of the triangle (w1 = leg1 = 3, w2 = leg2 = 5, w3 = hypotenuse = 7). So we have: L.A. = (15 x 3) + (15 x 5) + (15 x 7) L.A. = 15(3 + 5 + 7) L.A. = 225 Thus, we can also say that the lateral area of a prism is the product of the perimeter of its base with the height of the prism.