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How can you make $25.45 using the least number of bills and coins?
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1, a 25c coin.
Just one, a dime.
Three seems about right . . . a penny, a dime, and a half-dollar.
How can you make $25.45 using the least number of bills and coins?
2
Three
1, a 25c coin.
50p + 20p + 10p + 5p + 2p +2p = 6 coins
Just one, a dime.
To calculate the number of 10 cent coins needed to make $2.80, you would first convert $2.80 to cents, which is 280 cents. Then, you would divide 280 by 10 (the value of each coin) to find the number of coins needed. Therefore, you would need 28 10 cent coins to make $2.80.
In the minimum coin change problem using dynamic programming, the minimum number of coins required to make a given amount of change is calculated by finding the optimal combination of coins that add up to that amount. This involves breaking down the problem into subproblems and finding the minimum number of coins needed for each subproblem. The final answer is the minimum number of coins needed to make the given amount of change.
4 pennies, 1 quarter, and a dime.
The greatest number - would be 35 pennies (one-cent pieces)
It depends which currency you are using.
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