2(8)(10) + 2(8)(8) + 2(10)(8)
160 + 256 + 160
320 + 256
576 in. square
Least to greatest: inches, feet, yards
At least two fractions are needed to answer this.
There are 12 inches per foot. Therefore, the volume of sand required is 100 X 122 X 5 cubic inches or 7 X 104 cubic inches, to the number of significant digits justified by the least precisely stated data point, 5 inches. If all the integers specified are considered exact, then the answer is 72,000 cubic inches.
Nope - it's at least three inches too big on its smallest dimension !
At least two fractions are needed to determine a least common denominator.
If you cut the wrapping paper and stick it on the sides of the box, the minimum you will require is 540.3 sq inches.
Well, honey, to wrap that rectangular prism, you gotta find the surface area. Add up the area of all six sides: 2(8x8) + 2(8x10) + 2(8x10) = 320 square inches. So, you'll need at least 320 square inches of wrapping paper to cover that bad boy.
At least 10 inches.
you COULD completely cover the box with 88 square feet of paper, it would look pretty ugly because you would have to tape every edge though ;) btw, 88 sq ft is 12,672 square inches.
You can use them out of the original wrapping, at least that's what I do.
She is referring to the average penis size that she wants/likes. Females say that they don't want a penis that is less than 7 inches. Sexually it is felt that at least 7 inches is needed to be sexually gratified.
You will need at least 9.68 cubic yards of cement.
At least ten inches
8.43,8.45,8.64,8.9 .
The sealing material should extend least 2 inches past the edge of the wound.
Whether that's the length, the width, the diagonal, or the perimeter, you don't have enough information. To get the area of a rectangle, you need at least two measurements.
The LCM is 102.