It could be (2-ft x 20-ft).
Or it could be
1 x 21
3 x 19
4 x 18
5 x 17
6 x 16
7 x 15
8 x 14
9 x 13
10 x 12
11 x 11
or any one of an infinite number of other sets of dimensions,
as long as the length and width add up to 22.
You can't tell the length and width from the perimeter.
To find the perimeter of a rectangle, you can use the formula: P = 2(length + width). For a rectangle that is 4 feet in length and 3 feet in width, the perimeter would be P = 2(4 + 3) = 2(7) = 14 feet. Thus, the perimeter is 14 feet.
To find the perimeter of a rectangle, you can use the formula ( P = 2(length + width) ). For a rectangle with a length of 35 feet and a width of 30 feet, the perimeter would be ( P = 2(35 + 30) = 2(65) = 130 ) feet. Therefore, the perimeter of the rectangle is 130 feet.
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
5 feet
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter is 30 feet for this rectangle.
The width is 8 feet
To find the perimeter of a rectangle, you can use the formula: P = 2(length + width). For a rectangle that is 4 feet in length and 3 feet in width, the perimeter would be P = 2(4 + 3) = 2(7) = 14 feet. Thus, the perimeter is 14 feet.
To find the perimeter of a rectangle, you can use the formula ( P = 2(length + width) ). For a rectangle with a length of 35 feet and a width of 30 feet, the perimeter would be ( P = 2(35 + 30) = 2(65) = 130 ) feet. Therefore, the perimeter of the rectangle is 130 feet.
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
5 feet
30
20
44