It could be (2-ft x 20-ft).
Or it could be
1 x 21
3 x 19
4 x 18
5 x 17
6 x 16
7 x 15
8 x 14
9 x 13
10 x 12
11 x 11
or any one of an infinite number of other sets of dimensions,
as long as the length and width add up to 22.
You can't tell the length and width from the perimeter.
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
5 feet
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
20
It is 17 feet
The perimeter of a rectangle with a length of 8.5 feet and a width of 4.5 feet is 26.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The perimeter is 30 feet for this rectangle.
The width is 8 feet
You are describing a cuboid, not a rectangle. A rectangle has only two diminutions, length and width.
5 feet
If the dimensions of the rectangle are in feet, the perimeter will be in feet as well. The area will be in square feet. The area is length x width. The perimeter is 2 x (length + width) or 2 x length + 2 x width.
20
44
gt
15 feet.
63 feet