It would be 8.
Width X length.. typical deck goes out from house 10 feet, and a width of 12 feet that totals 120 sq.ft.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
Area = length x width Length = area/width
Length / Width
It is not possible to determine the width of the cell with just the length of the pointer provided. The width of the cell would depend on its specific shape and dimensions, which would require more information to calculate.
It would be 8.
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Width X length.. typical deck goes out from house 10 feet, and a width of 12 feet that totals 120 sq.ft.
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
The average length of an onion cell ranges from 0.25 mm or 250 microns to 0.4 mm or 400 microns. No one has actually measured the width of an onion cell but from the diameter of the field of view in a microscope and comparing the length to the width, I would say that the width is about a quarter or third of the length. Therefore, the width would have to be somewhere between 0.06 to 0.08 mm.
Area = length x width Length = area/width
Length / Width
Length and width
If Length * Width = Area, then Area ÷ width = Length
Area = (length) times (width)Length = (area) divided by (width)Width = (area) divided by (length)
No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.No. It has NO length, NO width, NO height. Only a position.