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Distance between (3, 0) and (0, -6)

= sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.

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Q: What is the length of 3 0 0 -6?
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What do you need to add to -6 to get 3?

9. -6+6=0 0+3=3 therefore -6+9=3


What is the next number in this pattern 9 6 3?

0 9-3=6 6-3=3 3-3=0


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The length of a rectangle is ten ft less than three times its width find the dimensions if the area is forty eight?

let the width be z so length is (3z-10) Area=length x width Area=48 z(3z-10)=48 3z2-10z-48=0 3z2-18z+8z-48=0 3z(z-6)+8(z-6)=0 (3z+8)(z-6)=0 z= - (8/3) which is not possible since dimensions can not be negative So z=6 Width=6 length=3x6-10=8 Dimension= 6 ft x 8 ft