Distance between (3, 0) and (0, -6)
= sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
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9. -6+6=0 0+3=3 therefore -6+9=3
0 9-3=6 6-3=3 3-3=0
6
3*6=18, 6*3=18, 18/3=6, 18/6=3, 6*0=0, 3*0=3, 1*8=8, 8*1=8
let the width be z so length is (3z-10) Area=length x width Area=48 z(3z-10)=48 3z2-10z-48=0 3z2-18z+8z-48=0 3z(z-6)+8(z-6)=0 (3z+8)(z-6)=0 z= - (8/3) which is not possible since dimensions can not be negative So z=6 Width=6 length=3x6-10=8 Dimension= 6 ft x 8 ft