Distance between (3, 0) and (0, -6)
= sqrt[(3 - 0)2 + (0 - -6)2] = sqrt(32 + 62) = sqrt(45) = 3*sqrt(5) or 6.71 approx.
To find the length of the line segment AB, you can use the distance formula: ( AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). For points A(0, 0) and B(6, 3), the calculation is ( AB = \sqrt{(6 - 0)^2 + (3 - 0)^2} = \sqrt{6^2 + 3^2} = \sqrt{36 + 9} = \sqrt{45} = 3\sqrt{5} ). Therefore, the length of AB is ( 3\sqrt{5} ).
9. -6+6=0 0+3=3 therefore -6+9=3
0 9-3=6 6-3=3 3-3=0
6
3*6=18, 6*3=18, 18/3=6, 18/6=3, 6*0=0, 3*0=3, 1*8=8, 8*1=8
The length varies, but it is about 3 to 6 inches long.
9. -6+6=0 0+3=3 therefore -6+9=3
Length = 13 units Midpoint = (0, 3.5)
0 9-3=6 6-3=3 3-3=0
If the midpoint of a horizontal line segment with a length of 8 is (3, -2), then the coordinates of its endpoints are (6, -2) and (0, -4).
The range is 6. (6 - 0 = 6)
6 = (0! +0! +0!)!
(0!+0!+0!)! =(1+1+1)! =3! =6 copyright An
Midpoint of line segment: (6, -2.5) Median line points: (6, -2.5) and (0, 0) Length of median line: 6.5
If a polynomial has factors x-6 and x-3 it will equal 0 if either factor equals 0 since the other factor then would be multiplied by 0. ie. 0 * (x-6)=0 and 0 * (x-3)=0. so x=3 or 6
A no. 6 haircut is typically about 3/4 inch in length.
6