If the box is a cube, a rectangular solid where l = w = h, then its diagonal d equals to
d = h√3 = 56√3 in ≈ 97 in
If the box is a rectangular solid where l ≠ w ≠ h, then its diagonal d equals to
d = √(l2 + w2 + h2).
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
8.9
If it is a rectangular box, then volume = length*breadth*height, where each is measured in inches. If it is a cylindrical box, then pi*radius2*height, where the radius and height are measured in inches.
Cubic inches in a box = volume of box (in cubic inches) = Length * Breadth * Height, where each of these three is given in inches.
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
You find cubic inches in a box by multiplying its length by its width, and by its height. The measurements for length, width, and height should all be in inches. This is known as the volume of the box.
I guess the diagonal length given is from one corner of the box to the opposite corner reached by traversing one length side, one edge side and one height side. Using Pythagoras, the length of the diagonal of the base (length by width) can be found. Using this diagonal and the height of the box, the diagonal from corner-to-opposite-corner of the box can be found using Pythagoras. However, as this [longer] diagonal is know, the height can be found by rearranging this last use of Pythagoras: Diagonal_base2 = length2 + width2 Diagonal_box2 = diagonal_base2 + height2 ⇒ height = √(diagonal_box2 - diagonal_base2 ) = √(diagonal_box2 - (length2 + width2)) = √(diagonal_box2 - length2 - width2) Now that the formula has been derived, plugging in (substituting) the various lengths will allow the height to be calculated.
8.9
If it is a rectangular box, then volume = length*breadth*height, where each is measured in inches. If it is a cylindrical box, then pi*radius2*height, where the radius and height are measured in inches.
Cubic inches in a box = volume of box (in cubic inches) = Length * Breadth * Height, where each of these three is given in inches.
Volume 36 cubic inches height 9 inches
The dimensions of the box are 23 inches in length, 40 inches in width, and 55 inches in height.
4 inches
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
Same as measuring a room. length times width times height. 10 inches long, 6 inches wide is 60 square inches times 5 inches tall which is 300 cubic inches. This is approximate, use the measurements of the shoebox and do the same math.
The area is 3025.56585 or about 3026.