The perimeter is 60 inches
The length is 20 units and the width is 10 units
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
The dimensions of the rectangle are 21 units by 9 units
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
The perimeter is 60 inches
20 cm
The length is 20 units and the width is 10 units
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
The dimensions of the rectangle are 21 units by 9 units
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
The length of the length will be 5 and the width will be 25.
There's no such thing as the length of a pentagon. But I don't think that'swhat you're really asking.A pentagon has five sides. If the sum of their lengths (perimeter) is 60, thenthe average length of the sides is 12.
60 and 62
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
A rectangle has 4 sides. Let the width of the rectangle be y. As the length of the rectangle is twice its width, it is 2y. The sum of the 2 sides that are the width: 2 * y = 2y The sum of the 2 sides that are the length: 2y * 2 = 4y The perimeter equals the 2 widths and the 2 breadths: 2y + 4y = 6y The perimeter: 6y = 60 cm So: y = 10 cm The length is 2y = 2 * 10 cm = 20 cm Answer: 20 cm