L + W = P/2 = 30. L = W + 5 so L = 17.5 and W = 12.5
The perimeter is 60 inches
The length is 20 units and the width is 10 units
To find the perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the area of the rectangle is given as 60 sq ft, and one of its sides is 6 ft. To find the other side, you divide the area by the given side length: 60 sq ft ÷ 6 ft = 10 ft. Now, you can calculate the perimeter by adding up all the sides: 6 ft + 10 ft + 6 ft + 10 ft = 32 ft.
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
The dimensions of the rectangle are 21 units by 9 units
The perimeter is 60 inches
20 cm
The length is 20 units and the width is 10 units
To find the perimeter of a rectangle, you need to add up the lengths of all its sides. In this case, the area of the rectangle is given as 60 sq ft, and one of its sides is 6 ft. To find the other side, you divide the area by the given side length: 60 sq ft ÷ 6 ft = 10 ft. Now, you can calculate the perimeter by adding up all the sides: 6 ft + 10 ft + 6 ft + 10 ft = 32 ft.
The perimeter of a rectangle is 2 x (length(L) + width). 150 = 2(L + 30) = 2L + 60 2L = 150 - 60 = 90 L = 45
Perimeter of a rectangle is 2(l+b).Area of rectangle is 216 centimeter square.
The dimensions of the rectangle are 21 units by 9 units
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
The length of the length will be 5 and the width will be 25.
60 and 62
There's no such thing as the length of a pentagon. But I don't think that'swhat you're really asking.A pentagon has five sides. If the sum of their lengths (perimeter) is 60, thenthe average length of the sides is 12.
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.