Q: What is the length of a rectangle when the area is 6x2 plus 19x plus 10 and the width is 3x plus 2?

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Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.

a rectangle

Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

Length = 3x - 2Width = x + 4Area = (length) times (width) = (3x - 2) (x + 4) = 3x2 + 10x - 8

Related questions

The area is the length times the width. The perimeter is two times the length plus two times the width.

The area is the length times the width. The perimeter is two times the length plus two times the width.

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The area is the length times the width. The perimeter is two times the length plus two times the width.

Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.

Perimeter: Add the length of the four sides. Area: Multiply length x width.

a rectangle

2 times length plus 2 times width = perimeterhalf the perimeter of a rectangle

Perimeter: (2*L)+(2*W) [length times two plus width times two] Area: L*W [length times width]

For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.

The formula for finding the area of a rectangle is A = LW. You can find the length by dividing the area by the width: A = LW x² + 50x = L * x (x² + 50x)/x = L X + 50 = L

L = 3x + 2y