Q: What is the length of a rectangle with an area of 5 square inches and a width of 10 inches?

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The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width

Its length is 1+ square root of 66 ft and its width is -1+ square root of 66 ft

The width is expressed in inches.

Width of the rectangle: 33.6/8 = 4.2 inches

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Related questions

The area of a rectangle is 56.25 square inches. The length of the rectangle is12.5 inches what is the width

if a rectangle is 450 square inches and the length is 24 inches what is the width?

The width is expressed in inches.

Its length is 1+ square root of 66 ft and its width is -1+ square root of 66 ft

2x4

The dimensions are: length = 15 inches and width = 7 inches Check: 15*7 = 105 square inches

Width of the rectangle: 33.6/8 = 4.2 inches

10 inches

They are: 3 inches and 5 inches respectively

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Area = Length * Width = 12*7 = 84 square inches.

A rectangle with one side that is double the length of the other side can be seen as two squares beside each other, that are half the area of the original rectangle, in this case 18 square inches / 2 = 9 square inches. The side of a square is the square root of the area, in this case the square root of 9 square inches, which is 3 inches. Now think about the rectangle again. What we just counted was the side of a square that made up one half of the rectangle you wanted to calculate the area of. So the shorter side of the rectangle is the same as our square, and the longer side is double the length. So the width of the rectangle is 3 inches, and the length is 2 * 3 inches = 6 inches. Or: Area = length x width (A=lw) Area = 18 (in2) Width = w Length = twice width (2w) 18 = (2w)w 18 = 2w2 9 = w2 3 = w The width is 3 in., the length (2w) is 6 in.