Q: What is the length of a rectangular patio that is 10 feet wide and a perimeter of 50 square feet?

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The perimeter of the patio is 24 feet.

AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET

length x width

A times A or A^2

area = length x width area = 90 feet 10 feet x 9 feet = 90 square feet.

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The perimeter of the patio is 24 feet.

If one side is twice the length of the other and the square footage is 800 I'd say one side is 20 feet and the other is 40.

10 ft

10 ft

89.55 square yards.

AREA = LENGTH x WIDTH LENGTH = 2 X WIDTH AREA = 2 x WIDTH X WIDTH = 900 900/2 = WIDTH X WIDTH 450 = WIDTH X WIDTH = WIDTH SQUARED WIDTH = SQUARE ROOT (450) = 21.21 FEET LENGTH = 42.42 FEET

Depends on the shape. If the space was 36x1, the perimeter would be 74. If the space was 18x2, the perimeter would be 40, and so on.

length x width

Measure the length and width of the patio area in metres. Times the length by the width to find the square area in metres. For instance: a patio measuring 10 metres by 8 metres: 10 x 8 = 80 square metres.

8 Feet

8 feet