Each side of the rhombus will have a length of 105/4 = 26.25 dm
Let the length be known as x: 2(x+4) = 105 2x+8 = 105 2x = 105-8 2x = 97 x = 48.5 Length = 48.5 units
Since the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
105/7 = 15 units
The dimensions work out as 7 units and 15 units
105 = 7 x 15.
Let the length be known as x: 2(x+4) = 105 2x+8 = 105 2x = 105-8 2x = 97 x = 48.5 Length = 48.5 units
Is a football pitch a 100 metres in length?
Since the dimensions of a standard football field are 105 x 68m, and a football field is a rectangle, then 105 + 68 + 105 + 68 = 346, so the perimeter is 346m.
Let the sides of the smaller triangle be x:- x = (983/3)-105 x = 222 and 2/3 meters or 222.666 .... recurring
70
It need not be a complex shape. You can have a rectangle with these properties. Just solve the two equations: 2a + 2b = 100 (for the perimeter) ab = 105 (for the area)
105
105/7 = 15 units
4391100
105 minutes
15 x 7 = 105...
Its is 125 meters in length and 65 in width.