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30 bc - 39 j =69 bc
I guess you are asking of the two sides which are not the hypotenuse, why the longer is root 3 times the shorter. Consider a 30, 60, 90 triangle ABC with ∠A = 30o, ∠B = 90o and ∠C = 60o and so side AC is the hypotenuse and BC is the shortest side. Reflect the triangle ABC in side BC to create triangle ABE. ∠EAB will be 30o, ∠ABE 90o and ∠BEA 60o. Side AE = AC. ∠EAC = ∠EAB + ∠BAC = 30o + 30o = 60o So triangle ACE is an equilateral triangle and thus side EC = AC Since EC = AC and EB = BC, EC=EB + BC ⇒ AC = BC + BC ⇒ AC = 2BC Using Pythagoras on triangle ABC to find length AB gives: AB2 + BC2 = AC2 ⇒ AB2 + BC2 = (2BC)2 ⇒ AB2 = 4BC2 - BC2 ⇒ AB2 = 3BC2 ⇒ AB = √3BC ie the shortest side is root 3 times the other non-hypotenuse side.
58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years
Let x be the length of side AB and y be the length of side BC. Given that the ratio of AB to BC is 4:3, we can express y in terms of x as y = (3/4)x. The perimeter of the triangle ABC is x + y + (x + (3/4)x) = 64 units. Simplifying, we get 2.75x = 64, so x = 64 / 2.75 = 23.27 units. Therefore, the shortest side of triangle ABC is the side AC, which is 20 less than the sum of AB and BC, so AC = x + y - 20 = 23.27 + 17.45 - 20 = 20.72 units.
It would be a straight line of length bc