Using the Pythagorean Theorem, we can find your answer.
a^2 + b^2 = c^2
9^2 + 40^2 = c^2
81 + 1600 = c^2
1681 = c^2
√1681 = c
41 = c
Your hypotenuse would be 41 feet.
The legs of a right triangle have the same length and the hypotenuse is 30 ft, each leg would be of length 21.21 ft.
5
I will assume that this is a right triangle and neither side length is the hypotenuse. In the case that this is a right triangle and neither side length given is for the hypotenuse, you would use tangent to solve for your angle measure. tan(Q) = the length of the side opposite of Q/the length of the side adjacent to Q. So for this answer: **NOTE: Side a is traditionally the side opposite to angle A.** tan(A) = a/b *where b is not the hypotenuse => tan(A) = 76.4/39.3 tan(A) = 1.94402... A = arctan(1.94402...) *arctan is the same thing as inverse tangent or tan^(-1) A ~= 62.78 Degrees * ~= means approximately. ***Extra stuff: tan = opposite/adjacent sin = opposite/hypotenuse cos = adjacent/hypotenuse
The length of the hypotenuse is sqrt (85) ; a little over 9 ft.
circumference? 40 pi ft.
50 ft providing that it is a right angle triangle.
The legs of a right triangle have the same length and the hypotenuse is 30 ft, each leg would be of length 21.21 ft.
5
I will assume that this is a right triangle and neither side length is the hypotenuse. In the case that this is a right triangle and neither side length given is for the hypotenuse, you would use tangent to solve for your angle measure. tan(Q) = the length of the side opposite of Q/the length of the side adjacent to Q. So for this answer: **NOTE: Side a is traditionally the side opposite to angle A.** tan(A) = a/b *where b is not the hypotenuse => tan(A) = 76.4/39.3 tan(A) = 1.94402... A = arctan(1.94402...) *arctan is the same thing as inverse tangent or tan^(-1) A ~= 62.78 Degrees * ~= means approximately. ***Extra stuff: tan = opposite/adjacent sin = opposite/hypotenuse cos = adjacent/hypotenuse
The length of the hypotenuse is sqrt (85) ; a little over 9 ft.
Isosceles triangles have two sides which are the same length and two angles which are equal. So if your right triangle has one side of length 2 feet, which is not the hypotenuse, then the remaining side must also be 2 feet long. We know that the square of the length of the hypotenuse is equal to the squares of the other two sides. 2 squared is 4. So the squares of the two sides are 4 + 4 which equals 8. Now we just find the square root of 8, which is 2.8284... So the length of the hypotenuse is 2.83 Feet (to two decimal places). Or, In a right isosceles triangle, the two base angles equal 45°. Since the length leg is 2 ft, then the hypotenuse length would be equal to 2√2 or approximately to 2.83 ft. sin 45° = leg/hypotenuse hypotenuse = 2/sin 45° hypotenuse = 2/(√2/2) hypotenuse = 4/√2 hypotenuse = 4√2/2 hypotenuse = 2√2 °
The hypotenuse is always the longest side so the triangle, as described, cannot exist.
Using Pythagoras' theorem the length of the hypotenuse is 10 feet which will be the length of the string needed
circumference? 40 pi ft.
The area formula is: Area = length x width Let: length = 40 ft width = 50 ft Then: A = 40 ft x 50 ft = 2000 ft²
sin(angle) = opposite/hypotenuse → hypotenuse = opposite/sin(angle) opposite = rise → hypotenuse = 40ft / sin 16.5° ≈ 140.84 ft
Length in feet times width in feet equals area in square feet. L=4 ft, W=10 ft; 4x10=40; Area=40 square feet.