The lowest number among the given values is 0.011. The other numbers are larger than 0.011, with 0.1 being the next lowest at 0.1.
1539026015
1001 0101
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
To convert decimal numbers to Binary-Coded Decimal (BCD), each digit is represented by its 4-bit binary equivalent. For instance, 74 in BCD is 0111 0100, 38 is 0011 1000, 8884 is 1000 1000 1000 0100, 275 is 0010 0111 0101, 165 is 0001 0110 0101, and 9201 is 1001 0010 0000 0001. To add an odd parity bit, count the number of 1s in the BCD representation; if it's even, add a 1, and if it's odd, add a 0. For example, 74 becomes 0111 0100 1 (5 ones), and 38 becomes 0011 1000 1 (5 ones).
Starting from the right, group the binary number into sets of 4. Then use the following conversions for each quartet: 0000 = 0 0001 = 1 0010 = 2 0011 = 3 0100 = 4 0101 = 5 0110 = 6 0111 = 7 1000 = 8 1001 = 9 1010 = A 1011 = B 1100 = C 1101 = D 1110 = E 1111 = F.
1539026015
1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 7 = 0111 8 = 1000 9 = 1001
16: 0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111
The Alphabet in Binary CodeLetterBinary CodeA01000001B01000010C01000011D01000100E01000101F01000110G01000111H01001000I01001001J01001010K01001011L01001100M01001101N01001110O01001111P01010000Q01010001R01010010S01010011T01010100U01010101V01010110W01010111X01011000Y01011001Z01011010LetterBinary Codea01100001b01100010c01100011d01100100e01100101f01100110g01100111h01101000i01101001j01101010k01101011l01101100m01101101n01101110o01101111p01110000q01110001r01110010s01110011t01110100u01110101v01110110w01110111x01111000y01111001z01111010
It is DAB not that hard really 0001 1 0010 2 0011 3 0100 4 0101 5 0110 6 0111 7 1000 8 1001 9 1010 A 1011 B 1100 C 1101 D 1110 E 1111 F and there you go
Collect them in groups of 4Then0000 = 0 0001 = 1 0010 = 2 0011 = 30100 = 4 0101 = 5 0110 = 6 0111 = 71000 = 8 1001 = 9 1010 = A 1011 = B1100 = C 1101 = D 1110 = E 1111 = F
Write each hexadecimal digit straight into binary: 5 = 0101 4 = 0100 2 = 0010 So 0x542 = 0101 0100 0010 = 10101000010 (without the spaces). Hex digit to binary conversion: 0 = 0000, 1 = 0001, 2 = 0010, 3 = 0011 4 = 0100, 5 = 0101, 6 = 0110, 7 = 0111 8 = 1000, 9 = 1001, a = 1010, b = 1011 c = 1100, d = 1101, e = 1110, f = 1111
Add the binary equivalent of 3 (0011) to each digit of the number in binary format. Ex: 1. Excess-3 of 6 is 0110(6) + 0011(3)= 1001(9) 2. Excess-3 of 12 is 0001 0010 + 0011 0011 = 0100 0101 (45)
1001 0101
Here are the binary numbers from zero to fifteen: 0 = 0000 1 = 0001 2 = 0010 3 = 0011 4 = 0100 5 = 0101 6 = 0110 7 = 0111 8 = 1000 9 = 1001 10 = 1010 11 = 1011 12 = 1100 13 = 1101 14 = 1110 15 = 1111
a)5b39+39a2=101 1011 0011 1001+11 1001 1010 0010=1001 0100 1101 1011 af=0 sf=1 zf=0 cf=0 b)5b39+dc49=101 1011 0011 1001+1101 1100 0100 1001=1 0011 0111 1000 0010 af=1 sf=0 zf=0 cf=1
100 1000 100 0001 101 0110 100 0101 100 0001 100 1110 100 1001 100 0011 100 0101 100 0100 100 0001 101 1001---------Binary Representation. 110 101 126 105 101 116 111 103 105 104 101 131.------Octal