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it's 2^10, which is decomposable in ten times the prime factor 2. If you replaced any of those 2s by a higher prime, the product would be greater than 2^10. And since there is no smaller prime than 2, this must be the smallest number that is decomposable in ten prime factors. If you meant 10 different prime factors, the answer would be the product of the ten smallest primes 2*3*5*7*11*13*17*19*23*29 which i am too lazy to calculate right now :)

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Q: What is the lowest number with ten prime factors?
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