The question is: "How do you bring 96/1440 to lowest terms?"
First, you find the greatest common divisor of 96 and 1440.
If we write (n,m) for the greatest common divisor, then we have the following rules:
1. (n,m) = (m,n), symmetry
2. (n,m) = (n-m,m), subtract one coordinate from the other
3. (n,m) = (n+m,m), add one coordinate to the other
4. (n,0) = n
Proof of 1. Trivial.
Proof of 2. Let k be a common divisor of n and m, such that n=k.r and m=k.s, then n-m = k.(r-s) is divisible by k and m is divisible by k, so all common divisors of n and m are common divisors of n-m and m.
Proof of 3. same idea as 2. Left as an exercise.
Proof of 4. Left as an exercise.
Hence, (96,1440) = (96,0) = 96.
Second, you find the quotient using the greatest common divisors and calculate the smallest terms, thus:
96/1440 = (96.1)/(96.15) = 1/15 in smallest terms.
<Feb 18, 2014 - B.C.>
20 over 96 reduced to its lowest term is 5/24
96/100 in its lowest term would be 24/25
The LCM is 1440.
Both are divisible by eight. So 8/11 would be the lowest fraction which could be represented in whole numbers.
24/96
20 over 96 reduced to its lowest term is 5/24
36/96 = 3/8
It's already in its lowest terms
96
96/25 is in its simplest form. It may also be written as 3 and 21/25.
96/100 in its lowest term would be 24/25
LCM(96, 144, 240) = 1440.
LCM of 96 and 45 is 1440.
The LCM is 1440.
Both are divisible by eight. So 8/11 would be the lowest fraction which could be represented in whole numbers.
24/96
85/96 is in its simplest form.