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2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
What is the multiplicative inverse of 3-4i divided by 5 plus 2i?
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
The division of two complex numbers arithematic operation requires the use of complex conjugate?
(3+2i)/(5+4i)If you multiply both sides by the conjugate of the denominator (5-4i), you get:(3+2i)(5-4i)/(5+4i)(5-4i)= (23-2i)/(25 + 16 +20i - 20i)= (23-2i)/41The denominator is now real, because the i terms cancelAs a general formula (easy to expand) this would be:(a+bi)/(c+di) = [(ac+bd) + (bc-ad)i] / (c^2 + d^2)It's a very easy method, but if you're the sort of person who loves using general formulas, there it is.
How do you find the magnitude of an integer?
The magnitude of an integer is the value of the integer with a positive (plus) sign. |5| = +5 = 5 |-5| = +5 = 5
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the conjugate of -5 4i?
-9
What is the sum of two complex conjugate number?
Since the imaginary parts cancel, and the real parts are the same, the sum is twice the real part of any of the numbers. For example, (5 + 4i) + (5 - 4i) = 5 + 5 + 4i - 4i = 10.
What is the multiplicative inverse of 3-4i divided by 5 plus 2i?
The multiplicative inverse of a number a is a number b such that axb=1 If we look at (3-4i)/(5+2i), we see that we can multiply that by its reciprocal and the product is one. So (5+2i)/(3-4i) is the multiplicative inverse of (3-4i)/(5+2i)
If Vector B is added to Vector A, the result is 6i+j. If B is subtracted from A, the result of -4i+7j. What is the magnitude of A?
11
Find the absolute value of the complex number z equals 3 plus 4i?
('|x|' = Absolute value of x) |3+4i| = √(32 + 42) = √(9+16) = √25 = 5 Thus |3+4i| = 5.
The division of two complex numbers arithematic operation requires the use of complex conjugate?
(3+2i)/(5+4i)If you multiply both sides by the conjugate of the denominator (5-4i), you get:(3+2i)(5-4i)/(5+4i)(5-4i)= (23-2i)/(25 + 16 +20i - 20i)= (23-2i)/41The denominator is now real, because the i terms cancelAs a general formula (easy to expand) this would be:(a+bi)/(c+di) = [(ac+bd) + (bc-ad)i] / (c^2 + d^2)It's a very easy method, but if you're the sort of person who loves using general formulas, there it is.
What is the conjugate of -6 plus 4i?
-6-4i.
How do you factor xsquared plus 16?
(x - 4i)(x + 4i) where i is the square root of -1
What is the conjugate of -8-4i?
The conjugate of -8-4i is -8+4i. It is obtained by changing the sign of the imaginary part of the complex number.
What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
What is conjugate of 4i open bracket -2 -3i close bracket?
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
