In a beam or length of material, we generally consider the longitudinal axis as the major axis for bending. But torsion will bend the material from the vertical, will twist it around that longitudinal axis. And lateral forces will bend the material across it axis of latitude.
The depth of section is major axis of that section. Prependicular to that depth is minor axis of that section. I think it helps you to understand. Regards, Vinay
The length of the major axis of an ellipse is equal to twice the length of the semi-major axis. If the semi-major axis is denoted as "a," then the major axis length is 2a. This axis is the longest diameter of the ellipse, stretching from one end of the ellipse to the other through the center.
The area of an ellipse with a major axis 20 m and a minor axis 10 m is: 157.1 m2
The length of the major axis of an ellipse is determined by the lengths of its semi-major and semi-minor axes. In this case, if the red line segment represents the semi-major axis (8), the length of the major axis would be twice that, which is 16. The blue line segment, being shorter (4), represents the semi-minor axis. Thus, the major axis of the ellipse is 16 units long.
To find the focus of an ellipse from its major axis, first identify the lengths of the semi-major axis (a) and the semi-minor axis (b). The distance from the center to each focus (c) can be calculated using the formula (c = \sqrt{a^2 - b^2}). The foci are located along the major axis, at coordinates ((\pm c, 0)) if the ellipse is centered at the origin and aligned with the x-axis.
The depth of section is major axis of that section. Prependicular to that depth is minor axis of that section. I think it helps you to understand. Regards, Vinay
basically,when you have bending suppose you take beam(I-section) and an axis along the beam now, 1.curl you fingers in the direction of bending 2.point the thumb perpendicular to your fingers 3.thumb would give you the flexural axis(bending axis)
Symmetrical bending occurs when a beam is loaded uniformly along its length, resulting in bending stresses that are equal on both sides of the beam's neutral axis. Unsymmetrical bending occurs when a beam is loaded unevenly, causing different magnitudes of bending stress on opposite sides of the beam's neutral axis.
The internal bending moment formula used to calculate bending stress in a beam is M I / c, where M is the bending moment, is the bending stress, I is the moment of inertia, and c is the distance from the neutral axis to the outermost fiber of the beam.
The relative sizes of the numerator and denominator have nothing to do with the major axis.
In the context of an ellipse, the vertical axis is the major axis.
we always design as per least radius of gyration rxx bcz for minimum capacity will be get in this axis. and design procedure is same as per IS 800:2007
The major axis is the axis that cuts, or goes between the two vertices of the hyperbola. The minor axis is perpendicular to the major axis and is an axis of symmetry. If the hyperbola is defined by: x^2/a^2 - y^2/b^2=1 where x^2 is x squared. Then the major axis is 2a units long, and the minor axis is 2b units long.
If you load it normal to the beam axis you get bending stresses ( tension and compression) and shear stresses. If you load it along the axis you get axial stress ( tension or compression)
The internal moment that tends to want a beam to bend around the center axis
The rotational inertia of your leg is greater when your leg is straight because the mass is distributed further away from the axis of rotation. When your leg is bending, the mass is closer to the axis of rotation, resulting in a lower rotational inertia.
The minor axis of a rectangular column or beam is the line that goes through the center. The minor axis will be shorter than the major axis.