The atomic mass of an atom is the mass of 6.011 X 10^23 atoms of that element.
I think its me myself
Sodium's atomic mass is 23. :)
2.3 = 23/10 and reduces to: 2 3/10
(17-4)+10=23 13+10=23
The mass of Mars is approximately 6.42 x 10^23 kilograms.
To find the mass of 3.01 x 10^23 formula units of Fe2O3, you first need to calculate the molar mass of Fe2O3. The molar mass of Fe2O3 is 159.69 g/mol. Then, you multiply the molar mass by the number of formula units given (3.01 x 10^23) to find the total mass. The mass of 3.01 x 10^23 formula units of Fe2O3 would be 4.81 x 10^25 grams.
32g
To calculate the mass of 3.011 x 10^23 nitrogen atoms, first find the molar mass of nitrogen which is 14.01 g/mol. Then, divide the number of atoms by Avogadro's number (6.022 x 10^23) to get the number of moles. Finally, multiply the number of moles by the molar mass to find the mass of the atoms. The calculation would be 3.011 x 10^23 / 6.022 x 10^23 = 0.5 moles, then 0.5 moles x 14.01 g/mol = 7.005 grams.
The atomic mass of an atom is the mass of 6.011 X 10^23 atoms of that element.
To find the total mass of 3.01 x 10^23 atoms of helium gas, you need to multiply the number of atoms by the atomic mass of helium. Helium's atomic mass is approximately 4 atomic mass units. So, the total mass would be 3.01 x 10^23 atoms * 4 amu.
To calculate the mass of 6.02 x 10^23 atoms of sulfur, you would first find the molar mass of sulfur (32.06 g/mol). Then, you would divide this molar mass by Avogadro's number to get the mass of one sulfur atom (in grams). Finally, multiply this value by 6.02 x 10^23 to find the mass of 6.02 x 10^23 atoms of sulfur.
Ganymede, which is one of Jupiter's moons, has a mass of about 1.48 x 10^23 kilograms.
The mass number of this atom is 23, the sum of the number of protons and neutrons.
2 atoms of lead have greater mass. Lead atoms are heavier than helium atoms, and the small amount of helium given in moles would still have a much smaller combined mass compared to the two lead atoms.
1 mole of any substance contains 6.022 x 10^(23) atoms/molecules. We have 1.5 x 10^(23) atoms Hence moles = 1.5 x 10^(23) / 6.022 x 10^(23) = 0.24908... moles(Mg) Also remember the eq'n moles = mass(g) / Ar Algebraically rearrange mass(g) = moles X Ar mass = 0.24908... X 24.3 (Ar of Mg ; from Periodic Table) Mass = 6.0528... g ~ 6 g
The mass ratio of an iron atom is 56, since the atomic mass of iron is approximately 55.85 atomic mass units.