There is no standard formula. It is necessary to partition the irregular hexagon into more convenient shapes such as triangles and quadrilaterals, find their areas and sum the results.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
First we assume it is a regular hexagon meaning all the angles are the same and the sides are the same length. Recalling that a regular hexagon can be broken up into 6 triangles, we find the area of the hexagon by finding the area of one triangle and multiply by six. (recall the area of triangle is Height x 1/2 Base ) You can also find the area of a hexagon using the formula Area==ap/2 where a is the apothem and p is the perimeter. But that just gives you the area of the 2 dimensional base, not the volume. To calculate the volume, multiply the area found above by the height of the hexagonal container.
Cut in half to make two trapazoids and find the area of one of the trapazoids. Don't forget to multiply the answers by two becasue you only found the area of half of the hexagon. If you want to get really tricky or forget the trapazoid formula then cut in in sixths and find the area of a triangle. Then multiply the answer by six.
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
There is no standard formula. It is necessary to partition the irregular hexagon into more convenient shapes such as triangles and quadrilaterals, find their areas and sum the results.
for perimeter add up the lengths of the six sides and for area divide the hexagon into six equilateral triangle, find the area of one, and multiply the product by six
The surface area of a hexagon is the same as its area. You will normally need to split the hexagon into triangles, find their area and sum these.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
the formula to find the area of any prism is to find the area of the base (a regular hexagon, meaning that all sides and angles are the same) and multiply by the height of the prism. To find the area of a hexagon you multiply the apothem by the perimeter of the hexagon, and then divide that by 2. the apothem is a line from the center point to the center of any side, forming a right angle with a side, it doesn't matter which one. Once you find the area of the hexagon, multiply it with the height.
First we assume it is a regular hexagon meaning all the angles are the same and the sides are the same length. Recalling that a regular hexagon can be broken up into 6 triangles, we find the area of the hexagon by finding the area of one triangle and multiply by six. (recall the area of triangle is Height x 1/2 Base ) You can also find the area of a hexagon using the formula Area==ap/2 where a is the apothem and p is the perimeter. But that just gives you the area of the 2 dimensional base, not the volume. To calculate the volume, multiply the area found above by the height of the hexagonal container.
Cut in half to make two trapazoids and find the area of one of the trapazoids. Don't forget to multiply the answers by two becasue you only found the area of half of the hexagon. If you want to get really tricky or forget the trapazoid formula then cut in in sixths and find the area of a triangle. Then multiply the answer by six.
irrgular hexgonal formula
The answer depends on the information available.
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
3/2*(shortest distance across the flats, passing through the center)*(length of one flat)