S= 3R multiplied by the square root of 3 (the result must be divided by 2.)
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There is no standard formula. It is necessary to partition the irregular hexagon into more convenient shapes such as triangles and quadrilaterals, find their areas and sum the results.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
First we assume it is a regular hexagon meaning all the angles are the same and the sides are the same length. Recalling that a regular hexagon can be broken up into 6 triangles, we find the area of the hexagon by finding the area of one triangle and multiply by six. (recall the area of triangle is Height x 1/2 Base ) You can also find the area of a hexagon using the formula Area==ap/2 where a is the apothem and p is the perimeter. But that just gives you the area of the 2 dimensional base, not the volume. To calculate the volume, multiply the area found above by the height of the hexagonal container.
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
Cut in half to make two trapazoids and find the area of one of the trapazoids. Don't forget to multiply the answers by two becasue you only found the area of half of the hexagon. If you want to get really tricky or forget the trapazoid formula then cut in in sixths and find the area of a triangle. Then multiply the answer by six.