Mean: 4.2
Median: 2
Mode: 1
Range: 8
Range: 8 Median: 7.5 Mode: 8
Mean: 4.2 Median: 2 Mode: 1 Range: 8
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Range: 7 Mean: 5.2 Median: 5 Mode: 2
Mean = 11 Median = 11 Mode = 4 Range = 18
Range: 8 Median: 7.5 Mode: 8
Mean: 4.2 Median: 2 Mode: 1 Range: 8
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
Range: 7 Mean: 5.2 Median: 5 Mode: 2
Mean = 11 Median = 11 Mode = 4 Range = 18
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
Mean= 5,9,6,6,1,1,8,4 = (1,1,4,5,6,6,8,9)/8 = 5 Median= (5+6)/2 =5.5 Mode= 1 ans 6. Range= (9-1) = 8
Mean: 7.44 Median: 7 Mode: 7 Range: 7
Median: 8 Mode: 8, 9 Range: 6
The median is 8.5. The mode is 8. The range is 14.
Mean: 11 Median: 11 Mode: 4 Range: 18