61, 85, 88, 101, 120
mean: 91
median: 88
There is no mode.
range: 59
Mean: 27.83 Median: 16.5 Mode: 14, 19, 20, 9, 101, 4 Range: 97
The median average of a set of numbers is the middle number when the numbers are listed in order. If there is an even number of numbers then the median is the mean average of the middle two: There are 2 numbers, therefore the median is the mean average of the middle two, which are the 1st and the 2nd → median = (98 + 101) ÷ 2 = 99.5
The median average of a set of numbers is the middle number when the numbers are listed in order. If there is an even number of numbers then the median is the mean average of the middle two. To find which is the median value add 1 to the number of items and divide by 2. If this is a whole number that is the median; otherwise the median is the mean average of the numbers that are at the whole part of this result and the next one: The dataset {95, 95, 98, 98, 98, 101, 102, 103, 104, 104} has 10 items, so the median is the mean average of the middle two. To find which is/are the median value::(10 + 1) /2 = 11/2 = 5.5 → the median is the mean average of the 5th and 6th items. → median = (98 + 101) ÷ 2 = 95.5
101 is the only palindromic number in the specified range.
The even numbers are given by tn = 2n, giving {2, 4, 6, ...} for n = 1, 2, 3, ... The median of an even number of data items is the mean of the middle two, which is the mean of the (100 / 2) = 50th and (100 / 2) + 1 = 51st even numbers, ie: median = mean(2 x 50, 2 x 51) = (2 x 50 + 2 x 51) / 2 = 2 x (50 + 51) / 2 = 50 + 51 = 101
Mean: 27.83 Median: 16.5 Mode: 14, 19, 20, 9, 101, 4 Range: 97
Median: 41 Mode: 898, 101, 3, 31, 51, 58, 13, 14 Range: 895
The median average of a set of numbers is the middle number when the numbers are listed in order. If there is an even number of numbers then the median is the mean average of the middle two: There are 2 numbers, therefore the median is the mean average of the middle two, which are the 1st and the 2nd → median = (98 + 101) ÷ 2 = 99.5
The median average of a set of numbers is the middle number when the numbers are listed in order. If there is an even number of numbers then the median is the mean average of the middle two. To find which is the median value add 1 to the number of items and divide by 2. If this is a whole number that is the median; otherwise the median is the mean average of the numbers that are at the whole part of this result and the next one: The dataset {95, 95, 98, 98, 98, 101, 102, 103, 104, 104} has 10 items, so the median is the mean average of the middle two. To find which is/are the median value::(10 + 1) /2 = 11/2 = 5.5 → the median is the mean average of the 5th and 6th items. → median = (98 + 101) ÷ 2 = 95.5
109 is the median, as it is the number in the middle when they are arranged in order.
Range = 101 - 5 = 96
Range = Max - Min = 101 - 48 = 53
When universities use a three-digit system of numbering courses, the easiest course would usually have the first number in the range, or "101". So basically, if something is followed by "101" it means it is for beginners.
In probability, there are three ways to look at instantiations (like: wins, points, the number two, odd integers) and determine which instantiations are the most likely to occur: mean, median and mode.Ex: let's take this set of basketball scores by team x: {100, 100, 101, 101, 101, 98, 99, 123, 118, 111 and 107}The Mode is the most frequently occuring score: 101 (3x)The Median is the "middle" score (order the 11 scores and select the middle) {98, 99, 100, 100, 101, 101, 101, 107, 111, 118 and 123}--->101The Mean is the sum of the scores divided by the number of scores, or sigma{set}/11 ~= 105.4The Average is calculated the same way as the Mean (by def. of Mean and Avg) ~=105.4A set of velocities is no different from any other instantiation set of real numbers, so "velocity" factors out of this proof (by def. of real numbers)Therefore, yes they do. []
The median is 94.
101 is the only palindromic number in the specified range.
shanghai 101?? u mean taibei 101.