The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
56, 57 and 58 have more than two factors.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64
1, 5, 11, 55 1, 2, 4, 7, 8, 14, 28, 56 1, 3, 19, 57 1, 2, 29, 58 1, 59
59! / 54! = 59 * 58 * 57 * 56 * 55 = 600766320
The mean is calculated by adding all the numbers together and dividing by the total count. In this case, the mean would be (52+53+54+55+55+56+57+57+57+59+60) / 11 = 56.09. The median is the middle number when the values are arranged in numerical order, which in this case is 56. The mode is the number that appears most frequently, which is 57 in this dataset.
The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
56, 57 and 58 have more than two factors.
The Prime numbers between 50 and 60 are 53 and 59.
51, 52, 53, 54, 55, 56, 57, 58, 59. Of those 53 and 59 are prime numbers.
when you put the numbers in order as described the number in the middle is the median. If 2 numbers are in the middle as in this case 56 and 58 you average them and get 57 as the median
Sticking with integers, numbers less than 60 but greater than 55 are 56, 57, 58 and 59.
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
The number of combinations is nCr = (59*58*57*56*55)/(5*4*3*2*1) = 5006386
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.