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The answer is 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386
56, 57 and 58 have more than two factors.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
There are 59C5 = 59*58*57*56*55/(5*4*3*2*1) = 5,006,386 combinations.
53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64