The supplement of an angle is found by subtracting the angle from 180 degrees. For angle B, which measures 32 degrees, the supplement can be calculated as follows: 180 - 32 = 148 degrees. Therefore, the measure of the angle supplement of B is 148 degrees.
The supplement of an angle is found by subtracting the angle from 180 degrees. Therefore, the supplement of a 32-degree angle is 180 - 32 = 148 degrees.
4X - 25, where X=32 4x 32 -25 =103 we know that sum of two supplementary angles is 180 degree so the supplement of 4X -25 = 180 - 103 = 77 degree
It is 32 degrees!
The third angle is [180-(32+70)] = 180-102 = 78
The interior angles of a 2-D triangle will always add up to 180 degrees. To determine the measure of the third angle: 180 - (32 + 75) = 73 degrees
The supplement of an angle is found by subtracting the angle from 180 degrees. Therefore, the supplement of a 32-degree angle is 180 - 32 = 148 degrees.
The supplement of an angle is the angle that, when added to the original angle, equals 180 degrees. In this case, the supplement of a 148-degree angle would be 180 degrees minus 148 degrees, which equals 32 degrees. So, the supplement of a 148-degree angle is a 32-degree angle.
148
148 A+
148
4X - 25, where X=32 4x 32 -25 =103 we know that sum of two supplementary angles is 180 degree so the supplement of 4X -25 = 180 - 103 = 77 degree
32 and 71 equals 103 subtract that from 180 and you get your answer of 77 degrees
An angle that measures 32 degrees is an acute angle
It is 32 degrees!
100.
The third angle is [180-(32+70)] = 180-102 = 78
Find the measure of the angle T, if the measure of the angle T is 20 more than four times its supplement. The supplement of T = (180-T) Write an equation for the statement: "angle T is 20 more than four times its supplement." T = 4(180-T) + 20 T = 720 - 4T + 20 T + 4T = 720 + 20 5t = 740 T = T = 148 degrees Check solution in original equation: 148 = 4(180-148) + 20 148 = 4(32) + 20 148 = 128 + 20