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4X - 25, where X=32 4x 32 -25 =103 we know that sum of two supplementary angles is 180 degree so the supplement of 4X -25 = 180 - 103 = 77 degree
It is 32 degrees!
The third angle is [180-(32+70)] = 180-102 = 78
The interior angles of a 2-D triangle will always add up to 180 degrees. To determine the measure of the third angle: 180 - (32 + 75) = 73 degrees
32 degrees
148
148 A+
148
The supplement of a 148-degree angle is a 32-degree angle.
4X - 25, where X=32 4x 32 -25 =103 we know that sum of two supplementary angles is 180 degree so the supplement of 4X -25 = 180 - 103 = 77 degree
32 and 71 equals 103 subtract that from 180 and you get your answer of 77 degrees
An angle that measures 32 degrees is an acute angle
It is 32 degrees!
100.
The third angle is [180-(32+70)] = 180-102 = 78
Find the measure of the angle T, if the measure of the angle T is 20 more than four times its supplement. The supplement of T = (180-T) Write an equation for the statement: "angle T is 20 more than four times its supplement." T = 4(180-T) + 20 T = 720 - 4T + 20 T + 4T = 720 + 20 5t = 740 T = T = 148 degrees Check solution in original equation: 148 = 4(180-148) + 20 148 = 4(32) + 20 148 = 128 + 20
The interior angles of a 2-D triangle will always add up to 180 degrees. To determine the measure of the third angle: 180 - (32 + 75) = 73 degrees