It is 16, the value halfway between the two middle numbers.
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∙ 6y agoThe median is 8.
-8 + 19 = 11
There are 8 numbers. So you need to find the average of the 4th and 5th numbers when they are placed in order. So, average of 16 and 19 = 17.5
The mode is the number which occurs most - so this is 20 The median is the middle number if you write them all in numerical order..... 5, 13, 13, 15, 18, 20, 20, 20 The answer is 16.5 which is in the middle of 15 and 18 To find the mean you add all the numbers up 5+13+13+15+18+20+20+20=124 then divide by the number of numbers in the range (8). 124/8 = 15.5
The median is 9.
Mean: 19 and 1/6 Median: 20 There is no mode.
12
The median is 8.
-8 + 19 = 11
The first 8 prime numbers are: 2 3 5 7 11 13 17 and 19 The median is: (7+11)/2 = 9
There are 8 numbers. So you need to find the average of the 4th and 5th numbers when they are placed in order. So, average of 16 and 19 = 17.5
The mode is the number which occurs most - so this is 20 The median is the middle number if you write them all in numerical order..... 5, 13, 13, 15, 18, 20, 20, 20 The answer is 16.5 which is in the middle of 15 and 18 To find the mean you add all the numbers up 5+13+13+15+18+20+20+20=124 then divide by the number of numbers in the range (8). 124/8 = 15.5
The median is 9.
8
11 13 17 19.
sorted: 1 2 7 9 11 15 19 20 number of items: 8 middle items: 9 and 11 average of middle items, or median: (9+11)/2 = 10
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.