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The median is the middle score in a set of data which is organised ascending (lowest to highest). In your set of data, it appears that this has already been done, which takes care of the first step. Then we count up the number of scores that have been recorded. In your case, this would be six. Since this is an even number, we take the 3rd and 4th scores, and find the average of them. So in this case:
64 73 79 82 87 110
79+82 = 161
161 / 2 =80.5
Therefore 80.5 is our median.
However, in a case where there is an odd number of scores, the middle number should be selected (i.e. when there is nine scores the fifth should be selected).
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What is the median of 94 79 83 78 70 66 68 75 53 54 79 59 83 91 64 65 71 62 86 90?
73 The median is the middle value, so I'll have to rewrite the list in order: 5354596264656668707175787979838386909194 There are 20 numbers in the list, so there is no "middle" number. So, you take the average of the middle two numbers, which is 71 and 75. So the median is 73.
How many numbers are there up to 100 where the two digits add to 10?
110
What are the prime numbers between 64 and 77?
There are 3 prime numbers between 64 and 77: 67 71 73.
What is 64 times 73?
64 multiplied by 73 is 4,672
What is the median of 72 75 78 72 73?
It is: 73
