8
8. In order: 4, 6, 7, 9, 10, 12 6 data items so median is mean of middle two: median = (7+9)/2 = 8.
The median is the number in the middle - same number of places from either left or right. You have 7 numbers, so median is the 4th from either side - the median is 9
your median would be 5 if you have an even amount of numbers you take n/2 and (n/2)+1 and average them together n=how many numbers you have so 4 4/2= the second number and (4/2)+1= the third number 4+6=10 10/2=5
the answer is 8
8
The median is the central value, 10.
The mean average is (6+12+10+4+3)÷5 = 7 The median average is middle number of {3, 4, 6, 10, 12} = 6 There is no mode average as every number appears with the same frequency (of 1).
7
8. In order: 4, 6, 7, 9, 10, 12 6 data items so median is mean of middle two: median = (7+9)/2 = 8.
The median is the number in the middle - same number of places from either left or right. You have 7 numbers, so median is the 4th from either side - the median is 9
your median would be 5 if you have an even amount of numbers you take n/2 and (n/2)+1 and average them together n=how many numbers you have so 4 4/2= the second number and (4/2)+1= the third number 4+6=10 10/2=5
To find the median of the numbers 4, 5, 7, 9, 10, and 12, you have to list the numbers from least to greatest and then find the middle number. So if you count them out or cross 1 number from each side, (4-12, 5-10) you're left with 7-9 as middle numbers / center numbers. Because the middle numberS is 7 and 9, you have to find what's between it to find the median. And we all know between 7 and 9, there is 8. So 8 is your median.
The average, median and mode of a list of numbers will be the same when the middle (or mean of the two middle numbers) is equal to the most common number in the list, and that number is also the mean. This assumes that the list has only a single mode. If you arrange such a list of numbers from least to greatest, the mode value will be grouped at the middle of the list, thus becoming the median as well. The average of the non-median values will be equal to the median/mode. Given a target mean/median/mode and a list length, you can construct an infinite number of lists that qualify. Here are some examples: 10 10 10 10 10 (or any list of only one number) 11 12 12 12 12 13 1 2 3 4 5 5 5 6 7 8 9
8
the answer is 8
If you have an even number of data points, the median is the mean of the middle two. eg, the median of {1, 2, 4, 6, 8, 10, 12, 16} is (6 + 8) ÷ 2 = 7.
The median of the four numbers is 10.