Arrange the numbers from least to greatest: 6, 7, 8, 8, 10, 10, 10. Get rid of each end number: 7, 8, 8, 10, 10. Do it again: 8, 8, 10. Do it again: 8 is your middle number and is therefore your median.
6 7 8 8 8 10 11 11 11 12 13 minimum-6 median-10 range-13-6=7 modes-8,11
7 = average of 6 and 8
8. In order: 4, 6, 7, 9, 10, 12 6 data items so median is mean of middle two: median = (7+9)/2 = 8.
Sample size: 12 Sorted sample: 3, 5, 6, 6, 7, 7, 8, 9, 9, 9, 10, 10 Middle numbers: 7, 8 Average of middle numbers, known as median: 7.5
It is 9.
8.
6 7 8 8 8 10 11 11 11 12 13 minimum-6 median-10 range-13-6=7 modes-8,11
7 = average of 6 and 8
8. In order: 4, 6, 7, 9, 10, 12 6 data items so median is mean of middle two: median = (7+9)/2 = 8.
median = 8 mean = 7 mean < median.
Sample size: 12 Sorted sample: 3, 5, 6, 6, 7, 7, 8, 9, 9, 9, 10, 10 Middle numbers: 7, 8 Average of middle numbers, known as median: 7.5
The median of a set of numbers is the middle one (if there are an odd number of them) or the mean average of the middle two (if there are an even number of them). The dataset {4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8, 9, 10, 11} has 14 elements, so the median is the mean average of the 7th and 8th numbers. The 7th and 8th numbers are 7 and 7, thus the median is (7 + 7) / 2 = 7.
14, 6, 8, 10, 9, 5, 7, 13 First re-arrange the terms into Rank Order. Hence 5,6,7,8,9,10,13,14. The MEDIAN is the Absolute middle term , which is (9+10) / 2 = 9.5 The MODE is is the most frequent term. As a;; terms occur with the same frequency of one. , then the Median is used as the Mode, Hence 9.5 again. THe MEAN is the sum of all the terms divided by the number of terms. Hence [5+6+7+8+9+10+13+14] / 8 => [72]/8 = 9 The means NB For good measure, the RANGE is 14 - 5 = 9 [
There are 6 numbers, so the median is the mean of the middle two: (7 + 8) ÷ 2 = 7.5
7.5
The median is 7.5
The median is the middle number when they are in order, so that is 8.