After putting them in order, cross out the 'ends' First 58 and 80 Then 58 and 74 You are left with 63 and 69 The median number is 66. The median is the number in the 'middle.'
The median value is: (52+58)/2 = 55
To find the median, you add up the set of numbers and divide that answer by the total number of numbers that are in the set. For this question, the answer is 318/6 = 53
58% of 20= 58% * 20= 0.58 * 20= 11.6
It is 60, the middle number.
Median: 41 Mode: 898, 101, 3, 31, 51, 58, 13, 14 Range: 895
Median = 58 Mode = 58 Range = 0
After putting them in order, cross out the 'ends' First 58 and 80 Then 58 and 74 You are left with 63 and 69 The median number is 66. The median is the number in the 'middle.'
The sum of two numbers between 20-40 is 58. The difference is 12
when you put the numbers in order as described the number in the middle is the median. If 2 numbers are in the middle as in this case 56 and 58 you average them and get 57 as the median
The median value is: (52+58)/2 = 55
You did not indicate a full year... 12/31/50: Sunday 12/31/51: Monday 12/31/52: Wednesday 12/31/53: Thursday 12/31/54: Friday 12/31/55: Saturday 12/31/56: Monday 12/31/57: Tuesday 12/31/58: Wednesday 12/31/59: Thursday As you can tell, through the 2 day skips in 1952 and 1956 they were leap years. Hope this helps !
1.871
To find the median, you add up the set of numbers and divide that answer by the total number of numbers that are in the set. For this question, the answer is 318/6 = 53
The GCF of 31 and 58 is 1.
You order the numbers in order of least to greatest then you just mark them off one by one on each side. when/if you get two numbers, you just pick the number in between the numbers. I.E. If you had the numbers 12, 58, 26, 84, 26, 84, and 39, you would write them out 12, 26, 26, 39, 58, 84, 84, then cross them out like this: 26, 26, 39, 58, 84; 26, 39, 58; 39; and 39 would be the median. if you had two numbers left, like 14 and 17, the median would be halfway between them, which would be 15.5.
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