0
9 22 4 16 10 34
Rearrange the terms in rank order.
Hence
4, 9, 10, 16, 22, 34.
Since there are an even number of terms, take the middle two and find the mid-point between them .
Hence
(10 + 16) / 2 = 13
'13' is the MEDIAN.
What else can I help you with?
What is the median of 29 34 42 44 14 34 7 6 34?
The median of 6, 7, 14, 29, 34, 34, 34, 42, 44 is 34.
What is 22 base 16 in base 10?
To convert the hexadecimal number 22 (base 16) to decimal (base 10), you can break it down as follows: 2 in the 16's place and 2 in the 1's place. This gives you (2 \times 16^1 + 2 \times 16^0 = 32 + 2 = 34). Therefore, 22 in base 16 is equal to 34 in base 10.
What is the third quartile q3 of the following distribution 4 5 33 10 12 14 34 43 21 22 21 22 44 29 16 18 20 24 26 29?
To find the third quartile (Q3) of the given distribution, first, sort the data in ascending order: 4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44. There are 20 data points, so Q3 is the median of the upper half (the top 10 values): 22, 22, 24, 26, 29, 29, 33, 34, 43, 44. The median of these values is the average of the 5th and 6th values (29 and 29), which gives Q3 = 29.
What is the lcm of 2 and 34?
The least common multiple of 2 and 34 is simply 34, because 34 is divisible by both 2 and 34.
Can the product of 16x 34 is like the product of 6 x 34 plus 10 x 34?
Yes, the product of (16 \times 34) can be expressed as the sum of the products (6 \times 34) and (10 \times 34). This is because (6 + 10) equals (16), so when you distribute (34) across both terms, it confirms that (16 \times 34 = (6 + 10) \times 34 = 6 \times 34 + 10 \times 34). Thus, the equality holds true.
What is the median of 13 14 16 17 21 22 34 45?
19
What is the median of 29 34 42 44 14 34 7 6 34?
The median of 6, 7, 14, 29, 34, 34, 34, 42, 44 is 34.
What is 22 base 16 in base 10?
To convert the hexadecimal number 22 (base 16) to decimal (base 10), you can break it down as follows: 2 in the 16's place and 2 in the 1's place. This gives you (2 \times 16^1 + 2 \times 16^0 = 32 + 2 = 34). Therefore, 22 in base 16 is equal to 34 in base 10.
What is the third quartile q3 of the following distribution 4 5 33 10 12 14 34 43 21 22 21 22 44 29 16 18 20 24 26 29?
To find the third quartile (Q3) of the given distribution, first, sort the data in ascending order: 4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44. There are 20 data points, so Q3 is the median of the upper half (the top 10 values): 22, 22, 24, 26, 29, 29, 33, 34, 43, 44. The median of these values is the average of the 5th and 6th values (29 and 29), which gives Q3 = 29.
What is the median of 20 22 24 26 28 30 32 34 and 36?
28
What is the mode mean range median of 25 36 12 10 10 44 15?
25 36 12 10 10 44 15 First rearrange the terms in rank order. Hence 10, 10, 12, 15, 25, 36, 44 MODE ; is the term that occurs most frequently (often). In this case '10'. MEDIAN : is the Absolute middle term . In this case '15'. There are three terms to either side of '15'. MEAN ; ; is the sum of all the terms divided by the number of terms. Hence [10 + 10 + 12 + 15 + 25 + 36 + 44 ] / 7 [152]7 = 21.71428.... ~ 21.7 RANGE ; is the difference between the largest and smallest terms 44 -10 = 34 .
Fourth arithmetic means between 40 and 10?
16, 22, 28 & 34 would appear to fit.
What is the median of 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35?
18 is the median of these numbers.
How is the product of 16 x 34 is like the product of 6 x 34 plus 10 x 34?
It's because 16 can be broken into 10 and 6. If you've delved into algebra, you've likely come across this while factoring: a(b+c) = ab+ac. Now assume that a is 34, b is 6, and 10 is c 34(10+6) = 34(10) + 34(6) Since 10+6 = 16: 34(16) = 34(10) + 34(6)
What is the lcm of 2 and 34?
The least common multiple of 2 and 34 is simply 34, because 34 is divisible by both 2 and 34.
Can the product of 16x 34 is like the product of 6 x 34 plus 10 x 34?
Yes, the product of (16 \times 34) can be expressed as the sum of the products (6 \times 34) and (10 \times 34). This is because (6 + 10) equals (16), so when you distribute (34) across both terms, it confirms that (16 \times 34 = (6 + 10) \times 34 = 6 \times 34 + 10 \times 34). Thus, the equality holds true.
What is the median between 21 23 29 32 34 36 38 40 45 45?
Hence the median of the above set is (21 + 23 + 29 + 32 + 34 + 36 + 38 + 40 + 45 + 45) / 10 = 343/10 = 34.3
