A segment need not be a bisector. No theorem can be used to prove something that may not be true!
The converse of perpendicular bisector theorem states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
1730
Yes, the distance formula for a line segment was derived from Pythagoras' theorem.
what is mid point theoram?
the line segment joining the mid point of two sides it is parallel and half of third side the line segment joining the mid point of two sides it is parallel and half of third side
If a segment bisects one side of a triangle and is parallel to another side, it bisects the third side as well.
A segment need not be a bisector. No theorem can be used to prove something that may not be true!
If M is the midpoint of segment AB, then AMis congruent to MB.
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
The converse of perpendicular bisector theorem states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
1730
If a point is on the perpendicular bisector of a segment, then it is equidistant, or the same distance, from the endpoints of the segment.
Yes, the distance formula for a line segment was derived from Pythagoras' theorem.
A segment that connects two midpoints of a polygon.
what is mid point theoram?
if segment ab is congruent to segment CD then segment ac is congruent to segment bd (only if points a, b, c, and d are all collinear)