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y = x2 - 2x + 10

This is a minimum when dy/dx = 0

dy/dx = 2x - 2 :

When 2x - 2 = 0 then 2x = 2 : x = 1

Substituting in the equation gives y = 12 - (2 x 1) + 10 = 1 - 2 + 10 = 9.

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15y ago

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Q: What is the minimum of y equals X2-2X plus 10?
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