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The missing number in the series 1 4 27 3125 is?

The missing number in the series 1, 4, 27, 3125 can be identified by observing the pattern of powers. Each number corresponds to a base raised to an increasing exponent: (1^1), (2^2), (3^3), and (5^5). Therefore, the missing number, which corresponds to (4^4), is 256.


If you have 1-4-27- -3125 what is the missing number?

44 = 256


What number is missing in the sequence 1 4 27 x 3125?

256


What is the missing number in the series 1 4 27 3125?

Missing number is 256 The series is 1,4,27,256,3125 i.e. 1, 2*2, 3*3*3, 4*4*4*4, 5*5*5*5*5


What is the next number in the series 1 4 27 256 3125 46656?

823,543 The pattern is n to the nth power.


What number goes in the blank 823543-46656-3125-256- -4-1?

27


What is the next number in the series 1 4 27......3125?

missing number is 256 1, 4, 27, 256, 3,125 then 46,656, 823,543 and so on ... 1¹ = 1 2² = 2 x 2 = 4 3³ = 3 x 3 x 3 = 27 so 4 x 4 x 4 x 4 = 16 x 16 = 36 + 60 + 160 = 256


1-4-27-256 what is the next number?

11 = 1 22 = 4 33 = 27 44 = 256 55 = 3125


What number is next in line 1 4 27 256?

312511 = 122 = 433 = 2744 = 25655 = 3125


What is the missing number in 25 18 22 27 the average in 22?

The missing number is 18


How Print serices1 4 27 256 3125 in c?

int main (void) { puts ("1 4 27 256 3125"); return 0; }


What is the missing number in the sequence 823543 - 46656 - 3125 - 256 - - 4 - 1?

The number is 27. (33) The sequence shows the lowest 7 nonzero values for the exponential series nn, i.e. 1 to the first power, 2 to the 2nd power, up to 7 to the 7th power. 1*1=1 2*2=4 3*3*3=27 4*4*4*4=256 5*5*5*5*5=3125 6*6*6*6*6*6=46656 7*7*7*7*7*7*7=823543