The answer depends on which number is missing. Even if the location of the gap is know, there are infinitely many possible solutions. The solutions listed below are polynomials of the lowest degree.
First:
5 using the rule Un = (-4n3 + 48n2 - 128n + 99)/3
Second:
0 using the rule Un = (-7n3 + 84n2 - 209n + 138)/6
Third:
21.666 (recurring) using the rule Un = (3n3 - 23n2 + 84n - 61)/3
Fourth:
50 using the rule Un = (-11n3 + 90n2 - 121n + 48)/6
Fifth:
65 using the rule Un = (-4n3 + 36n2 - 44n + 15)/3
64 It is a series of cubes 13, 23, 33, 43, 53 etc
64 because the series is 13, 23, 33, 43, 53, 63
The sequence interval is 2 4 6 8 ( this is the difference of number). so the missing number is -1 if I'm not mistaken.
Arithmetic- the number increases by 10 every term.
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
64 It is a series of cubes 13, 23, 33, 43, 53 etc
64 because the series is 13, 23, 33, 43, 53, 63
The sequence interval is 2 4 6 8 ( this is the difference of number). so the missing number is -1 if I'm not mistaken.
Arithmetic- the number increases by 10 every term.
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
9 (between 8 and 16).
13 ...23 ...33 ...43 ...53=125■
They are perfect cubes: 13, 23, 33, 43, and 53.
There seems to be a number missing between 78 and 213. Please check and resubmit.
The sequence is the cube of successive numbers starting at 1; 13 - 23 - 33 - 43 - 53 - 63 -...
If the question is, What is the missing number in the sequence 7, 11, 23, ?, 167? Then each number is 3 times the previous number then deduct 10. 3 x 7 = 21 - 10 = 11 3 x 11= 33 - 10 = 23 3 x 23 = 69 - 10 = 59......the missing number 3 x 59 = 177 - 10 = 167 3 x 167 = 501 - 10 = 491....the next number in the sequence.
By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.