5; mode is the number that appears the most frequently in a set of numbers
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∙ 13y ago{2, 2, 5, 6, 7} {2, 2, 5, 6, 7} {2, 2, 5, 6, 7} {2, 2, 5, 6, 7}
There is no mode in this list.
That set has no mode.
Median: 3 Mode: 1 Range: 6
2, 6 and 7 do not have a mode. A mode is the most common number, but there is only one of each number so there is no mode.
{2, 2, 5, 6, 7} {2, 2, 5, 6, 7} {2, 2, 5, 6, 7} {2, 2, 5, 6, 7}
There is no mode in this list.
That set has no mode.
Mean: 5 Median: 5 Mode: 3
Median: 3 Mode: 1 Range: 6
all the answers is 5 in this question mode is=5 media=5 mean=5
2, 6 and 7 do not have a mode. A mode is the most common number, but there is only one of each number so there is no mode.
That set has no mode.
the mean of five numbers is 6 and the mode is 7 what are the numbers
Mean = 6 Mode = 5.
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
There is no mode. This sequence is not finding modes.