There is no mode.
There is no mode in this list.
Mean 5 Median 7.5 Mode 5 Range 4
That set has no mode.
Both 8 and 4
5
Think of 5 positive integers that have a mode of 4 and 6, a median of 6 and a mean of 7.
There is no mode.
There is no mode in this list.
Mean 5 Median 7.5 Mode 5 Range 4
That set has no mode.
Both 8 and 4
With extreme difficulty, that is, you cannot.The mode depends entirely upon the data items and the same mode can be found for different pairs of means and medians; similarly for any given pair of mean and median, there are many modes possible.example:The data sets {1, 1, 3, 4, 5, 6, 7, 8, 10}:mean: (1 + 1 + 3 + 4 + 5 + 6 + 7 + 8 + 19) ÷ 9 = 6median: [1, 1, 3, 4] , 5, [6, 7, 8, 19] = 5mode: [1, 1], 3, 4, 5, 6, 7, 8, 19 = 1and {1, 2, 3, 4, 5, 6, 7, 7, 19}:mean: (1 + 2 + 3 + 4 + 5 + 6 + 7 + 7 + 19) ÷ 9 = 6median: [1, 2, 3, 4], 5, [6, 7, 7, 19] = 5mode: 1, 2, 3, 4, 5, 6, [7, 7], 19 = 7both have mean 6 and median 5, but the first has a mode of 1 and the second a mode of 7 - you cannot tell the mode from the mean and median.
Mean: 7 Median: 6 Mode: 1, 9, 4, 7, 5, 3, 16, 11
0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11 mean = 6 and 3/11 median = 7 mode = 9
That set has no mode.
Mean: 7.44 Median: 7 Mode: 7 Range: 7