Mean: 9 Median: 8.5 Mode: 14, 6, 8, 10, 9, 5, 7, 13
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
That set has no mode.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
mode is the value that is repeated most often and therefore in this example it would be 8
Mean: 9 Median: 8.5 Mode: 14, 6, 8, 10, 9, 5, 7, 13
mean: 9 ordered sample: 7, 8, 8, 10, 12 median: 8 mode: 8 range: 12 - 7 = 5
The median is 8.5. The mode is 8. The range is 14.
8, 8, 8, 10, 14, 15 The mean is 10.5 The median is 9. The mode is 8. The range is 7.
That set has no mode.
Mean: 7.44 Median: 7 Mode: 7 Range: 7
There is no mode. This sequence is not finding modes.
11 and 7 because they appear twice. (mode is how many times a number appears)
The mean is 9.6. The median is 8.5. The mode is 8. The range is 14.Rewrite the values from least to greatest:6, 7, 8, 8, 8, 9, 9, 10, 11, 20Mean is the average:(6 + 7 + 8 + 8 + 8 + 9 + 9 + 10 + 11 + 20)/10 = 96/10 = 9/6Median is the middle value:the mean of5th and 6thnumber= (8 + 9)/2 = 17/2 = 8.5Mode is thenumber that is repeated often:8 is repeated thrice so 8 is the mode.Range is the difference of the greatest value and the least value = 20 - 6 = 14
It depends: 7/8/9/10 can be: 7/(8/(9/10)) = 7/(80/9) = 63/80, or 7/((8/9)/10) = 7/(8/90) = 7/(4/45) = 315/4 (7/8)/(9/10) = 70/72 = 35/36 (7/(8/9))/10 = (63/8)/10 = 63/80 ((7/8)/9)/10 = (7/72)/10 = 7/720 * * * * * There is an "and" between 8 and 9 so the question, in fact, refers to 7/8 + 9/10 which is not ambiguous. 7/8 + 9/10 = 35/40 + 36/40 = 71/40 = 1 and 31/40
That set has no mode.