There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
First put them in ascending order. 1, 5, 7, 9, 9, 12, 14, 15, 18 Mean is 10 Median is 9 Mode is 9 Range is 17
mode
18/21 x 15 is 12 6/7
6.
There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
One possibility: 5, 6, 7, 7, 7, 12, 12, 13, 14, 15, 16, 18
First put them in ascending order. 1, 5, 7, 9, 9, 12, 14, 15, 18 Mean is 10 Median is 9 Mode is 9 Range is 17
mode
5/12:7/18= (5/12)/(7/18)= (5/12)*(18/7)= 15/14
7 occurs more than any other number, so it is the mode.
Well, honey, if you want a set of numbers that fit those criteria, how about 7, 7, 7, 12, 12, 12, 12, 12, 12, 12, 18, 18? You've got your mode of 7, median of 12, maximum of 18, and a range of 13. Looks like I just served you a math cocktail with a side of sass. Cheers!
well, the mode is basically asking you what number appears the most frequently. 6, 6, 7, 8, 9, 9, 9, 12, 12, 12, 15 in the sequence, the mode would either be 9 or 12 because those are the numbers that appear the most frequently.
18/21 x 15 is 12 6/7
6.
Mean = 7.9 Median = 7 and 8 Mode = 4 and 12 Range = 2 to 15.
The mode is 15 because it occurs most often