whenever carbon atom forms four covalent bonds the basic structure is tetrahedral because carbon in such cases is sp3 hybridized.
Tetrahedral
There are no lone pairs and it's tetrahedral.
The molecular geometry is octahedral.
The molecular geometry of C2H2Br2 is trigonal planar.The molecular geometry of C2H2Br2 is trigonal planar.
The molecular geometry of secl2 is BENT.
Tetrahedral
There are no lone pairs and it's tetrahedral.
Yes, CBr4 is a molecular compound. It consists of one carbon atom bonded to four bromine atoms through covalent bonds.
The molecular geometry is octahedral.
The molecular geometry of C2H2Br2 is trigonal planar.The molecular geometry of C2H2Br2 is trigonal planar.
The molecular geometry of secl2 is BENT.
The molecular geometry of HClO is bent.
The molecular geometry of N2O2 is linear.
CBr4 is a molecular compound because it consists of nonmetallic elements (carbon and bromine) bonded together through covalent bonds. Ionic compounds typically form between a metal and a nonmetal, with electrons being transferred rather than shared.
The molecular geometry of IF4- is square planar.
The molecular geometry of NHF2 is trigonal pyramidal.
See-saw is the molecular geometry, and trigonal bi-pyramidal is the orbital geometry.