The numbers are increasing in line with the 3 times (multiplication) table.6-7 is plus 1.7-10 is plus 3.10-16 is plus 6.16-25 is plus 9.Next in the 3 times table is 12. So, the next number will be 25 + 12.The answer is 37.
100
10 and 11
-8 minus 10 -8 plus 10
10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.
The numbers that don't appear on a 10 by 10 multiplication table are the squares of integers greater than 10. For example, 121 (1111), 144 (1212), 169 (13*13), and so on.
(-10) + (-7) + (-14) = -31
The numbers are increasing in line with the 3 times (multiplication) table.6-7 is plus 1.7-10 is plus 3.10-16 is plus 6.16-25 is plus 9.Next in the 3 times table is 12. So, the next number will be 25 + 12.The answer is 37.
13
100
Look at the multiplication table. 5, 10, 15 ...
It is not! There is not an efficient form of multiplication to add 3 to 7.7*(13/7) = 10 can hardly be described as a more efficient operation!
Um, not sure how to do that, but you can create a sort of "table" in C++ by using multidimensional arrays. Below is an example of how to create a two-dimensional array: int myArray[10] [10]; You can add more dimensions to the array in order to increase its storage capacity.
10 and 11
-8 minus 10 -8 plus 10
5, 10, 15, 20, 25, 30, 35, 40
199