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If the interior of a polygon is 1080 degrees how many sides does it have?
the sum of the angles in a polygon = the number of sides n less 2 x 180, or (n-2)*180. so the answer to the Q is as follows 1080 = 180*(n-2); n = 2+ (1080/180)
If the sum of interior angles a regular polygon is 1080 degrees how many diagonals does this polygon have?
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20
How many sides does a polygon whose interior angles equal 1080 degrees?
It has 8 sides - it is an octagon (either regular or irregular, convex or concave).The formula for the sum of interior angles of an n-sided polygon is 180(n-2)1080 = 180 (n-2)6 = n-2n = 8
How many sides does a polygon have if its angles add up to 1080 degrees?
8?n-2 (180)
What shape does the interior angles add up to 1080 degrees?
n-sided polygon, interior angles (2n - 4) right angles or 180n - 360 degrees. 180n - 360 = 1080 180n = 1440 n = 8 It's an octagon.
How many sides does a polygon with an interior angle measure of 1080 have?
If the polygon has n sides, the sum of its interior angles is 180*(n-2) = 1080 So n-2 = 1080/180 = 6 And therefore n = 8
If the interior of a polygon is 1080 degrees how many sides does it have?
the sum of the angles in a polygon = the number of sides n less 2 x 180, or (n-2)*180. so the answer to the Q is as follows 1080 = 180*(n-2); n = 2+ (1080/180)
How many sides does a polygon have if the sum of the measures of its interior angles is 1080?
the sum of the interior angles of a polygon is 180(n-2), where n is the number of sides.1080 = 180(n-2)6 = n-2n = 8The polygon has 8 sides, it is an octagon.
If the sum of interior angles a regular polygon is 1080 degrees how many diagonals does this polygon have?
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20
If the sum of an interior angle measures of a polygon is 1080 degree's how many sides does the polygon have?
The sum of the interior angles of a polygon is 2n - 4 right angles - where n is the number of sides. So, 1080° = 1080/90 = 12 right angles If 2n - 4 = 12 then 2n = 16 : n = 8 The number of sides is 8.
If the sum of the interior angles of a polygon equals 1080 degree's what is the measure of each interior angle of the polygon?
Sum of interior angles = (n-2)*180 degrees = 1080 deg So (n-2) = 1080/180 = 6 => n = 8. The polygon is, therefore, an octagon. However, there is no reason to assume that the interior angles of this polygon are all the same - they could all be different with the only constraint being their sum. IF, and that is a big if, the polygon were regular, then all its angles would be equal and each interior angle = 1080/8 = 135 degrees.
If the sum of the interior angles of a regular polygon is 1080 degrees how many sides does this polygon have?
Formula to find sum of interior angles (when n = number of sides): 180(n-2) Sub in total and solve for n: 180(n-2) = 1080 180n-360 = 1080 180n = 1080 + 360 180n = 1440 180n/180 = 1440/180 n = 8 Thus, the number of sides is 8 and it is a hexagon.
How many sides does a polygon whose interior angles equal 1080 degrees?
It has 8 sides - it is an octagon (either regular or irregular, convex or concave).The formula for the sum of interior angles of an n-sided polygon is 180(n-2)1080 = 180 (n-2)6 = n-2n = 8
How many sides does a polygon have if its angles add up to 1080 degrees?
8?n-2 (180)
What is the sum of the measures of the angles of an octagon?
The 8 interior angles of an octagon add up to 1080 degrees
What is the mean of the angle measures in an octagon?
The sum of the interior angles in a polygon with n sides is 180º(n-2). That means that for an octagon, the answer is 180(8-2) = 180(6) = 1080. The sum of the inside angles is 1080 degrees.
If a polygon measures 1080?
8
