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the sum of the angles in a polygon = the number of sides n less 2 x 180, or (n-2)*180. so the answer to the Q is as follows 1080 = 180*(n-2); n = 2+ (1080/180)
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20
It has 8 sides - it is an octagon (either regular or irregular, convex or concave).The formula for the sum of interior angles of an n-sided polygon is 180(n-2)1080 = 180 (n-2)6 = n-2n = 8
8?n-2 (180)
n-sided polygon, interior angles (2n - 4) right angles or 180n - 360 degrees. 180n - 360 = 1080 180n = 1440 n = 8 It's an octagon.