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What would the name for a polygon that measures 1080 degrees?
An octagon has interior angles of 1080 degrees.
What is the sum of angles in octagon?
Sum of angles in a regular polygon = (#sides - 2) * 180. Sum of Octagon angles = (8-2) * 180 = 1080
What is the sum of the interior angles of a regular octagon?
The interior angles of any polygon add up to the number of sides - 2, times 180 degrees. For an octagon this is 180 x 6 with is 1080 degrees, thus: The sum of the interior angles of a regular octagon is 1080 degrees
If the sum of interior angles a regular polygon is 1080 degrees how many diagonals does this polygon have?
If the polygon has n sides, the sum of its interior angles is 180*(n - 2) degrees. [Whether the polygon is regular or not is irrelevant] So, 180*(n - 2) = 1080 (n - 2) = 6 n = 8 Then number of diagonals = n*(n - 3)/2 = 8*5/2 = 20
How may degrease are in a regular octagon?
The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees. 1080 degrees
What would the name for a polygon that measures 1080 degrees?
An octagon has interior angles of 1080 degrees.
If the sum of an interior angle measures of a polygon is 1080 degree's how many sides does the polygon have?
The sum of the interior angles of a polygon is 2n - 4 right angles - where n is the number of sides. So, 1080° = 1080/90 = 12 right angles If 2n - 4 = 12 then 2n = 16 : n = 8 The number of sides is 8.
How many sides does a polygon have if the sum of the measures of its interior angles is 1080?
the sum of the interior angles of a polygon is 180(n-2), where n is the number of sides.1080 = 180(n-2)6 = n-2n = 8The polygon has 8 sides, it is an octagon.
If a polygon measures 1080?
8
What is the sum of angles in octagon?
Sum of angles in a regular polygon = (#sides - 2) * 180. Sum of Octagon angles = (8-2) * 180 = 1080
If the sum of the interior angles of a polygon equals 1080 degree's what is the measure of each interior angle of the polygon?
Sum of interior angles = (n-2)*180 degrees = 1080 deg So (n-2) = 1080/180 = 6 => n = 8. The polygon is, therefore, an octagon. However, there is no reason to assume that the interior angles of this polygon are all the same - they could all be different with the only constraint being their sum. IF, and that is a big if, the polygon were regular, then all its angles would be equal and each interior angle = 1080/8 = 135 degrees.
What polygon has interior angles that measure 1080 degrees?
The interior angles of an octagon add up to 1080 degrees
What is the total of all the measures of all the angles in a regular octagon?
Interior angles add up to 1080 degrees Exterior angles add up to 360 degrees So: 1080+360 = 1440 degrees
What is the sum of the interior angles of a regular octagon?
The interior angles of any polygon add up to the number of sides - 2, times 180 degrees. For an octagon this is 180 x 6 with is 1080 degrees, thus: The sum of the interior angles of a regular octagon is 1080 degrees
What is the sum of the measures of the angles of an octagon?
The 8 interior angles of an octagon add up to 1080 degrees
If the sum of the interior angles of a polygon is 1080 how many sides does the polygon have?
8
The sum of the interior angles of a polygon measure 1080°. What is the name of the polygon?
octagon
