What is the net electric flux through the torus (i.e. doughnut shape) of the figure (Figure 1) Assume that Q100nC and q and minus6.0nC.?

Answer 1

To determine the net electric flux through the torus, we can use Gauss's Law, which states that the electric flux through a closed surface is proportional to the enclosed charge. If the torus does not enclose any charge (meaning the total charge inside is zero), then the net electric flux through the torus will also be zero, regardless of the charges outside it. Given that the charges are ( +100 , \text{nC} ) and ( -6.0 , \text{nC} ), the net charge inside the torus would be ( 100 , \text{nC} - 6.0 , \text{nC} = 94 , \text{nC} ). Therefore, the net electric flux through the torus would be ( \frac{94 , \text{nC}}{\varepsilon_0} ), where ( \varepsilon_0 ) is the permittivity of free space.