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The conditional constant= 1.8*1010
Barium.
The question is poorly specified, since the given triangle can be right angled at A or C. If it is right angled at A, then bc2 = ab2 + ac2 so that ab2 = 100 - 16 = 84 and ab = sqrt(84) = 9.165 Or it is right angled at C, and ab2 = bc2 + ca2 = 100 + 16 = 116 so that ab = sqrt(116) = 10.770
The net ionic equation is SO42- + Ca2+ CaSO4.
H2SO4(aq) + CaI2(aq) -> CaSO4(s) + 2HI(aq)
The net ionic equation is SO42- + Ca2+ CaSO4.
The complete ionic equation for this reaction is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq)
2H+ + SO42- + Ca2+ + 2I- CaSO4 + 2H+ + 2I
The net ionic equation of the reaction given is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq).
CaSO4 is an ionic compound because it contains two ions namely CA2+ and SO42-.
Complete Ionic Equation. 2K+(aq) + SO42-(aq) + Ca2+(aq) + 2I-(aq) --> 2K+(aq) + 2I-(aq) + CaSO4(s) Net Ionic Equation Minus the Spectator Ions K+ and I-. Ca2+(aq) + SO42-(aq) --> CaSO4(s)
The net ionic equation for the reaction between Na2SO4 and CaCl2 is: Ca2+ + SO4^2- → CaSO4 This reaction involves the formation of calcium sulfate (CaSO4) precipitate.
Complete ionic equation: Ca^2+(aq) + 2OH^-(aq) + 2H^+(aq) + SO4^2-(aq) → CaSO4(s) + 2H2O(l) Net ionic equation: Ca^2+(aq) + 2H^+(aq) + SO4^2-(aq) → CaSO4(s) + 2H2O(l)
2Na+(aq) + SO42-(aq) + Ca2+(aq) + 2Cl-(aq) CaSO4(s) + 2Na+(aq) + 2Cl-(aq)
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.