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A picture 8 inches long of 6 inches width is to be enlarged so that its length will be 12 inches what is the width in inches of the enlarged picture?
Ratio of new length to old length = 12/8 = 3/2 So ratio of new width to old width must be 3/2 New width/Old width = 3/2 so New width = Old Width * 3/2 = 6 inches*3/2 = 9 inches
What is the area of a photo that measures 3 by 5 inches?
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
What if you decrease the length of a rectangle by 50 percent but leave the width alone how is the area affected?
It is decreased by half. If you decrease the width by half and leave the length alone, you get the same result.
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
How do you you get the length if you have the area and the width?
Area = length x width Length = area/width
A photo that is 8 inches wide and 12 inches long is enlarged to a poster if the width is enlarged to 24 inches what is the length of the poster?
2/1
A picture 8 inches long of 6 inches width is to be enlarged so that its length will be 12 inches what is the width in inches of the enlarged picture?
Ratio of new length to old length = 12/8 = 3/2 So ratio of new width to old width must be 3/2 New width/Old width = 3/2 so New width = Old Width * 3/2 = 6 inches*3/2 = 9 inches
What is the area of a photo that measures 3 by 5 inches?
The area of a rectangle is length times width. If length and width are in inches, the area will be square inches.
How do you find the percent of a whole?
times the length by the width
When a photo is reduced or enlarged its length and width ratio is usually remains the same Auelia wants to enlarge a 4 inch by 6 inch photo so that it has a width of 15 inches Use a ratio table?
Beautiful. You copied the set-up and the suggestion perfectly, but skipped the question. Anyway, the answer is 10. Now all you have to do is find the question again.
A picture 8 inches long and 6 inches wide is to be enlarged so that its length will be 12 inches?
Then the width has to be 9 in
A picture 8 inches long and 6 inches wide is to be enlarged so that its length will be 12 inches What is the width in inches of the enlarged picture?
9 inches7.5 inches wide
What if you decrease the length of a rectangle by 50 percent but leave the width alone how is the area affected?
It is decreased by half. If you decrease the width by half and leave the length alone, you get the same result.
What are the dimensions if the area is 216 and The length is 50 percent longer than width?
8
What are the dimensions of a table if the perimeter is 36 and the length is 5 times the width?
perimeter = length + length + width + width = 2*length + 2*width = 36 length = 5*width 2*(5*width) + 2*width = 36 12*width = 36 width = 3 length = 15
How do you you get the length if you have the area and the width?
Area = length x width Length = area/width
Where is the length and width location?
Length and width
