Given any number it is easy to find a rule based on a polynomial of order 7 such that the first seven numbers are as listed in the question and the eighth is the given number. That is, it is easy to find a rule so that any number can be the "next" in the sequence.
The polynomial of order six that fits is
Un = (n6 - 15n5 + 115n4 - 405n3 + 964n2 - 660n + 240)/240 and
accordingly, U8 = 379.
They are: 0, -5, -10
1, 2, 5, 10, 19, 38, 95, 190.
1 x 190, 2 x 95, 5 x 38, 10 x 19
280
30, 42, 38
They are: 0, -5, -10
the next three numbers are 180 540 and 1620=)
219
1, 2, 5, 10, 19, 38, 95, 190.
There is no number pattern in 781013. But there is a number pattern in the numbers 7, 8, 10, 13. 7+1=8 8+2=10 10+3=13 Can you see the pattern? And the next number in this sequence would be ... ?
The pattern seems to be +10 then -5. Therefore the next two numbers would be 26 and 36.
The multiples of ten from 10 to 190 inclusive are 10, 20, 30, ..., 190. The average arithmetic mean of these numbers can be calculated by adding all the numbers together and then dividing by the total count of numbers. In this case, there are 19 numbers from 10 to 190, and the average arithmetic mean is 100.
The pattern 1, 10, 100, 1000 next four numbers would be 10000, 100000, 1000000, 10000000.
The pattern is +5, -7... the answer is 6
These are all the whole numbers that go into 190 evenly: 1, 2, 5, 10, 19, 38, 95, 190.
1 x 190, 2 x 95, 5 x 38, 10 x 19
-12, 14, -16